MATH SOLVE

2 months ago

Q:
# Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the equation using the slope-intercept form.

Accepted Solution

A:

Answer:The answer to your question is: y = -2/3 x + 6 or 2x + 3y -18 = 0Step-by-step explanation: Point (-9, 12)Perpendicular to y = 3/2 x -1/2then slope = m = 3/2 but we change it, so m = -2/3 y -12 = -2/3 (x + 9) 3(y -12) = -2( x + 9) 3y - 36 = -2x - 18 General equation 2x + 3y -36 + 18 = 0 2x + 3y - 18 = 0slope y-intercept 3y = -2x -18 +36 3y = -2x + 18 y = -2/3 x + 18/3 y = -2/3x + 6