Q:

Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the equation using the​ slope-intercept form.

Accepted Solution

A:
Answer:The answer to your question is:     y = -2/3 x + 6   or 2x + 3y -18 = 0Step-by-step explanation: Point (-9, 12)Perpendicular to y = 3/2 x -1/2then    slope = m = 3/2   but we change it,  so  m = -2/3                y -12 = -2/3 (x + 9)               3(y -12) = -2( x + 9)                3y - 36 = -2x - 18   General equation      2x + 3y -36 + 18 = 0                                       2x + 3y - 18 = 0slope y-intercept           3y = -2x -18 +36                                        3y = -2x + 18                                         y = -2/3 x + 18/3                                         y = -2/3x + 6